3^3.5^3-20.{300-[540-2^3.(7^8:7^6.7^0)]}
Những câu hỏi liên quan
32.53-20.{300-[540-23(78:76+70)]}
32 . 53 - 20{300 - [540 - 23 (78 : 76 + 70)]}
= 9 . 125 - 20{300 - [540 - 8(72 + 70)]}
= 9 . 125 - 20{300 - [540 - 8(49 + 1)]
= 9 . 125 - 20{300 - [540 - 8.50]
= 9 . 125 - 20{300 - [540 - 400]}
= 9 . 125 - 20{300 - 140}
= 9 . 125 - 20. 160
= 1125 - 3200 = -2075
\(=9\cdot125-20\cdot\left\{300-\left[540-8\cdot\left(7^2+1\right)\right]\right\}\)
\(=1125-20\cdot\left\{300-\left[540-8\cdot\left(49+1\right)\right]\right\}\)
\(=1125-20\cdot\left[300-\left(540-8\cdot50\right)\right]\)
\(=1125-20\cdot\left[300-\left(540-400\right)\right]\)
\(=1125-20\cdot\left(300-140\right)\)
\(=1125-20\cdot160\)
\(=1125-3200\)
\(=-2075\)
Bài1:Thực hiện phép tính:
a,(2^4.3.5^2):{450:[450-(4.5^3-2^3.5^2)]}
b,3^3.5^2-20{90-[164-2.(7^8:7^6+7^0)]}
c,[(18^7:18^6-17).2022-1986].5.1^2022-13^2.2020^0
Bài2:Tìm x:
a,(2^x+1)^2+3.(2^2+1)=2^2.10
b,3.(x-7)+2.(x+5)=41
(GIÚP MIK VỚI Ạ)
Bài 1.
\(a,\left(2^4\cdot3\cdot5^2\right):\left\{450:\left[450-\left(4\cdot5^3-2^3\cdot5^2\right)\right]\right\}\)
\(=\left(16\cdot3\cdot25\right):\left\{450:\left[450- \left(4\cdot125-8\cdot25\right)\right]\right\}\)
\(=\left(48\cdot25\right):\left\{450:\left[450-\left(500-200\right)\right]\right\}\)
\(=1200:\left[450:\left(450-300\right)\right]\)
\(=1200:\left(450:150\right)\)
\(=1200:3\)
\(=400\)
\(---\)
\(b,3^3\cdot5^2-20\left\{90-\left[164-2\cdot\left(7^8:7^6+7^0\right)\right]\right\}\)
\(=27\cdot25-20\left\{90-\left[164-2\cdot\left(7^2+1\right)\right]\right\}\)
\(=675-20\left\{90-\left[164-2\cdot\left(49+1\right)\right]\right\}\)
\(=675-20\left[90-\left(164-2\cdot50\right)\right]\)
\(=675-20\left[90-\left(164-100\right)\right]\)
\(=675-20\left(90-64\right)\)
\(=675-20\cdot26\)
\(=675-520\)
\(=155\)
\(---\)
\(c,\left[\left(18^7:18^6-17\right)\cdot2022-1986\right]\cdot5\cdot1^{2022}-13^2\cdot2020^0\)
\(=\left[\left(18-17\right)\cdot2022-1986\right]\cdot5\cdot1-169\cdot1\)
\(=\left(1\cdot2022-1986\right)\cdot5-169\)
\(=\left(2022-1986\right)\cdot5-169\)
\(=36\cdot5-169\)
\(=180-169\)
\(=11\)
Bài 2.
\(a) (2^x+1)^2+3\cdot(2^2+1)=2^2\cdot10\\\Rightarrow (2^x+1)^2+3\cdot(4+1)=4\cdot10\\\Rightarrow (2^x+1)^2+3\cdot5=40\\\Rightarrow (2^x+1)^2+15=40\\\Rightarrow (2^x+1)^2=40-15\\\Rightarrow (2^x+1)^2=25\\\Rightarrow (2^x+1)^2= (\pm 5)^2\\\Rightarrow \left[\begin{array}{} 2^x+1=5\\ 2^x+1=-5 \end{array} \right.\\ \Rightarrow \left[\begin{array}{} 2^x=4\\ 2^x=-6 (vô.lí) \end{array} \right. \\ \Rightarrow 2^x=2^2\\\Rightarrow x=2\)
Vậy \(x=2\).
\(---\)
\(b)3\cdot(x-7)+2\cdot(x+5)=41\\\Rightarrow 3\cdot x+3\cdot(-7)+2\cdot x+2\cdot5=41\\\Rightarrow 3x-21+2x+10=41\\\Rightarrow (3x+2x)+(-21+10)=41\\\Rightarrow 5x-11=41\\\Rightarrow 5x=41+11\\\Rightarrow 5x=52\\\Rightarrow x=\dfrac{52}{5}\)
Vậy \(x=\dfrac{52}{5}\).
\(Toru\)
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33.53- 20 . {300-[546-23.(78:76+70)]}
33.53-20.{300-[546-23.(78:76+70)]}
= 33.53-20.{300-[546-23.(72+1)]}
= 33.53-20.[300-(546-23.50)]
= 33.53-20.[300-(546-400)]
= 33.53-20.(300-146)
= 33.53-20.154
= 3375-3080
= 295.
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47-[(45.2^4-5^2.12):14]
50-[(20-2^3):2+34]
10^2-[60:(5^6:5^4-3.5)]
50-[(50-2^3.5):2+3]
10-[(8^2-48).5+(2^3.10+8)]:28
8697-[3^7,3^5+2(13-3)]
2011+5[300-(17-7^2)]
695-[200+(11-1^2)]
129-5[29-(6-1^2)]
2010-2000:486-2(7^2-6)]
dài thế này làm đến tết chắc vẫn chưa xong
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Bạn đăng từ bài thôi , nhiều quá sao làm nổi
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Xem thêm câu trả lời
3^3.5^3-209300-9546-2^3(7^8:7^4-7^0)))
tính
33.53- 20 . {300-[546-23.(78:76+70)]}
\(3^3.5^3-20.\left\{300-\left[546-2^3.\left(7^8:7^6+7^0\right)\right]\right\}\)
= \(27.125-20.\left\{300-\left[546-8.50\right]\right\}\)
= \(3375-20.\left\{300-\left[546-400\right]\right\}\)
= \(3375-20.\left\{300-146\right\}\)
= \(3375-20.154=3375-3080=295\)
Đáp án hoàn toàn chính xác đấy.
Chúc bạn học tốt :))
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33.53-20.{ 300-[ 546-23.(78:76+70)]}
=-98-20.{300- [546-8.50]}
=-98-20.{300-[546-400]}
=-98-20.{300-146}
=-98-20.154
=-3178
Chúc bạn học tốt 
Khanh Nhí
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\(=\)\(3^3.5^3-20.\left\{300-\left[546-2^3.\left(7^8:7^6+7^0\right)\right]\right\}\)
\(=\)\(27.125-20.\left\{300-\left[546-2^3.\left(49+1\right)\right]\right\}\)
\(=\)\(3375-20.\left\{300-\left[546-8.50\right]\right\}\)
\(=3375-20\left(300-146\right)\)
\(=3375-20.154\)
\(=3375-3080\)
\(=295\)
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Xem thêm câu trả lời
6 tháng 12 2021 lúc 19:17
.Thực hiện phép tínha) 47 – [(45.24 – 5 2 .12):14]b) 50 – [(20 – 2 3 ) : 2 + 34]c) 102 – [60 : (56 : 54 – 3.5)]d) 50 – [(50 – 2 3 .5):2 + 3]e) 10 – [(82 – 48).5 + (23 .10 + 8)] : 28f) 8697 – [37 : 35 + 2(13 – 3)]g) 2011 + 5[300 – (17 – 7)2 ]h) 695 – [200 + (11 – 1)2 ]k) 2345 – 1000 : [19 – 2(21 – 18)2 ]l) 128 – [68 + 8(37 – 35)2 ] : 4m) 568 – {5[143 – (4 – 1)2 ] + 10} : 10n) 107 – {38 + [7.32 – 24 : 6+(9 – 7)3 ]}:15o) 307 – [(180 – 160) : 22 + 9] : 2p) 205 – [1200 – (42 – 2.3)3 ] : 40q) 177 :[2....
Đọc tiếp
.Thực hiện phép tính
a) 47 – [(45.24 – 5 2 .12):14]
b) 50 – [(20 – 2 3 ) : 2 + 34]
c) 102 – [60 : (56 : 54 – 3.5)]
d) 50 – [(50 – 2 3 .5):2 + 3]
e) 10 – [(82 – 48).5 + (23 .10 + 8)] : 28
f) 8697 – [37 : 35 + 2(13 – 3)]
g) 2011 + 5[300 – (17 – 7)2 ]
h) 695 – [200 + (11 – 1)2 ]
k) 2345 – 1000 : [19 – 2(21 – 18)2 ]
l) 128 – [68 + 8(37 – 35)2 ] : 4
m) 568 – {5[143 – (4 – 1)2 ] + 10} : 10
n) 107 – {38 + [7.32 – 24 : 6+(9 – 7)3 ]}:15
o) 307 – [(180 – 160) : 22 + 9] : 2
p) 205 – [1200 – (42 – 2.3)3 ] : 40
q) 177 :[2.(42 – 9) + 32 (15 – 10)]
r) [(25 – 2 2 .3) + (32 .4 + 16)]: 5
i) 129 – 5[29 – (6 – 1)2 ]
j) 2010 – 2000 : [486 – 2(72 – 6)]
s) 125(28 + 72) – 25(32 .4 + 64)
t) 500 – {5[409 – (23 .3 – 21)2 ] + 103 } : 15
Sao bạn bỏ một khoảng trống giữa các số 5 2 với 2 3v?
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3^x.5^3-20.{300-[546 - 2^3.(7^8:7^6+7^0)]}
Các bạn ơi giúp mình vs trình bay đầy đủ cho mình nha!!!!!!!
Thực hiện phép tính
33.53-20.{300-[546-23.(78-76+70)]}
626500:{502:[178-4.(35-21:3)]}
\(3^3\cdot5^3-20\cdot\left\{300-\left[546-2^3\cdot\left(7^8-7^6+7^0\right)\right]\right\}\)
\(=3^3\cdot5^3-20\cdot\left\{300-\left[546-2^3\cdot5647153\right]\right\}\)
\(=3^3\cdot5^3-20\cdot\left\{300-\left[546-45177224\right]\right\}\)
\(=3^3\cdot5^3-20\cdot\left\{300--45176678\right\}\)
\(=3^3\cdot5^3-20\cdot45176978\)
\(=3375-903539560\)
\(=-903536185\)
\(626500:\left\{50^2:\left[178-4\cdot\left(35-21:3\right)\right]\right\}\)
\(=626500:\left\{50^2:\left[178-4\cdot\left(35-7\right)\right]\right\}\)
\(=626500:\left\{50^2:\left[178-4\cdot28\right]\right\}\)
\(=626500:\left\{50^2:\left[178-112\right]\right\}\)
\(=626500:\left\{50^2:66\right\}\)
\(=626500:\frac{1250}{33}\)
\(=\frac{82698}{5}\)
CHUC BAN HOC TOT >.<
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